Chords equidistant from the centre of a circle are equal to length prove it
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let us suppose that the chords are parallel.
join center with the ends of the chords.
so 2 triangles will be formed in which all sides expect chords will be equal reason radii of the circle.
angles at center by chords will be equal as chords are parallel so angles at center will be opposite angles.
so by SAS triangles are congruent so both chords will be equal.
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