CHSE board 2020 .........
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Answer:
0.09 uF
Explanation:
when in parallel- Ceq1=C1+C2+C3=0.9
when in series-Ceq= Ceq1* C4/(Ceq1+C4)=0.09uF
where c1,c2,c3 are capacitors in parallel and c4 is in series with their resultant Ceq1.
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