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An electric oven of 2 kW power rating is operated in a domestic electric
circuit (220 V) that has a current rating of 5 A. What result do you
expect? Explain.
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Answer:
Power = V×I
2kW = 220 × I
I = 2000/220
I = 9.09 A
As the amount of current flowing in the conductor is more than 5 A, the fuse will get broken and hence the circuit will get open.
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