Question

cient -
Find the equation of straight line
which slope is 3/5 and intercept on
y-axis is 3-
(1) 3x - 5y +15=0
(2) 4x - 5y +15=0
(3)x+y+15=0​

Answer 1

Answer:

(1) 3x - 5y + 15 = 0

Step-by-step explanation:

The equation of the line with slope m and intercept on y-axis c is:

y = mx + c

So, the equation of the line with slope 3/5 and intercept on y-axis 3 is:

$y = \frac{3}{5} x + 3$

Multiply both sides by 5.

5y = 3x + 15

Write it in the standard form (ax + by + c = 0).

3x - 5y + 15 = 0

So, correct answer is (1).