Cinnabar (HgS) is a prominent ore of HgS. How many grams of mercury are present in 225g of pure HgS ? Molar mass of Hg and S are 200.6 g/mol and 32 g/mol respectively . Explain the answer with proper steps.
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Molar mass of Hg = 200.6 g mol-1
Molar mass of S = 32 g mol-1
Molar mass of cinnabar (HgS) = 200.6 + 32 = 232.6 g mol-1
Mass of Hg present in 232.6 g of HgS = 200.6 g
Mass of Hg present in 225 g of HgS = 200.6232.6×225 = 194.044 g
Hence , 194.044 g of Hg is present in 225 g of pure HgS.
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Molar mass of S = 32 g mol-1
Molar mass of cinnabar (HgS) = 200.6 + 32 = 232.6 g mol-1
Mass of Hg present in 232.6 g of HgS = 200.6 g
Mass of Hg present in 225 g of HgS = 200.6232.6×225 = 194.044 g
Hence , 194.044 g of Hg is present in 225 g of pure HgS.
HOPE IT HELPS YOU IF HELPED PLZ FOLLOW ME AND PLZ MARK THIS ANSWER AS BRAINLIST.....
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