Question

Cinnabar (HgS) is a prominent ore of mercury. How many grams of mercury are present in 225 g of pure HgS? Molar mass of Hg and S are 200.6 g mol-1 and 32 gmol-1 respectively.​

Answer 1

Question

Cinnabar (HgS) is a prominent ore of mercury. How many grams of mercury are present in 225 g of pure HgS? Molar mass of Hg and S are 200.6 g mol-1 and 32 gmol-1 respectively.​

Answer:

Molar mass of HgS = 200.6 + 32 = 232.6 -

This contains 200.6 g of Mercury

If 232.6 g of HgS contains 200.6 g Hg

∴  225 g of HgS will contain = (225 x 200.6) ÷ 232.6

                                                =  194.05 g

Answer 2

Explanation:

1 mole of HgS there is one mole of Hg. So in 0.94 moles of HgS there will be 0.94 moles of Hg. As mass is asked we know mass=moles× molecular mass=0.94×200.6=194.04 gram. So it exists 194.94 gram Hg in 225 gram HgS.

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