Circle 0, = circle 0,. If the radius of circle 0, = 5 cm, then the radius
of circle O, is
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0
Answer:
b
Step-by-step explanation:
B
6 cm
Radius of a circle is 5 cm.
Therefore OB = 5 cm.
Perpendicular drawn to the chord from the centre bisects the chord.
Therefore AM = MB
Triangle OMB is right angled triangle at M
∠OMB=90∘
By Pythagoras theorem;
OB2=OM2+MB2
MB=OB2−OM2
MB=52−42
MB=3cm
So, the length of chord AB=2.(MB)=6cm.
Option B will be the answer.
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