Circle A has a diameter of 9 inches, a circumference of 28.26 inches, and an area of 63.585 square inches. The diameter of circle B is 5 inches, the circumference is 15.70 inches, and the area is 19.625 square inches..
Part A: Using the formula for circumference, solve for the value of pi for each circle. (4 points)
Part B: Use the formula for area and solve for the value of pi for each circle. (4 points)
Part C: What observation can you make about the value of pi for circles A and B? (2 points)
Answers
This is the answer of questions
Concept
Circumference - The circumference of a circle is the length of the circle's boundary. If you cut a circle and straighten it, the length of the edge will be the length of the circumference. The formula for calculating perimeter is Circumference = 2πr
Where r is the radius of the circle
Area - The area of a circle is the area occupied by the circle in the two-dimensional plane. This is easily determined using the formula
where r is the radius of the circle.
Given
We have been given that circle A of diameter 9 inches having circumference of 28.26 inches and an area of 63.585 square inches.Circle B of diameter 5 inches having circumference of 15.70 inches, and the area of 19.625 square inches.
Find
We are asked to determine the value of pi by using circumference and area formula .
Solution
Part A :-
We will use the formula of the circumference of the circle which is given by
....(1)
For circle A , and circumference = 28.26 inches
Putting these values in equation (1) , we get
For circle B , and circumference = 15.70 inches
Putting these values in equation (1) , we get
Part B :-
We will use the formula of the area of the circle which is given by
...(2)
For circle A , and Area = 63.585 square inches
Putting these values in equation (2), we get
For circle B , and Area = 19.625 square inches
Putting these values in equation (2), we get
Part C :-
The value of pi for both of the circle is same which is 3.14 by using circumference as well as area formula .
Therefore , the value of pi is constant which is equals to 3.14 .
#SPJ2