Question

Circle A with equation x^2+y^2+4x+6y-0 is given. A second circle with centre E intersects the smaller circle at B on the x-axis. EB is the radius of circle E and EB is also a tangent to circle A at B. What is the value of EC/EA

Answer 1

Step-by-step explanation:

Taking CA as radius of small circle , we can say that at x axis we are getting coordinates (x,0)

Now the given equation to you is x^2+y^2+4x+6y=0,

so we know the formula that if two points are a diameter then

(x-x1)(x-x2)+(y-y1)(y-y2)=0

Here you must see that y=0 from above case , you will get the expression and solve for x from where you will get the radius