Question

Circle bisecting circumference of another circle

Answer 1

Let us consider the equation of bisecting circle to be "S1"...and the equation of bisected circle be "S2"

S1: x²+y² +4x+22y+l

S2: x²+y²-2x+8y-m

In order to calculate the value of "l+m"......we first need to calculate the value of common tangent...... Let us denote the eqn of common tangent with "L"

The eqn of common tangent will be = S1-S2

So eqn of common tangent is= x²+y²+4x+22y+l - (x²+y²-2x+8y-m)

Eqn of common tangent = 6x+14y+(l+m)=0

Also the centre of the bisected circle should lie on the common tangent.....

Centre of bisected circle = (1,-4). (-g,-f)

Putting the coordinates of centre of the circle in eqn of common tangent.....

6(1)+14(-4)+(l+m)=0

6-56+(l+m)=0

-50 +(l+m)=0

l+m=50

Answer 2

what do you want to ask is not clear .Can u explain??