Question

Circle C1 passes through the centre of circle C2 and
is tangential to it. If the area of C, is 4 cm^2, then the
area of C2 is

Answer 1

Answer:

Answer of the questions is 12.26

Answer 2

Area of Circle $C_2$ is $16 \ cm^2$.

Step-by-step explanation:

Given:

Area of Circle $C_1 = 4\ cm^2$

Let the radius of circle $C_1$ be $r_1$

Area of circle is given by π times square of radius.

framing in equation form we get;

$4= \pi {r_1}^2\\\\{r_1}^2= \frac{4}{\pi}$

Taking square root on both side we get;

$\sqrt{{r_1}^2}= \sqrt{ \frac{4}{\pi}}\\\\r_1= \sqrt{\frac{4}{\pi}} \ cm$

Now $r_2 = 2\times r_1 = 2\times \sqrt{\frac4{\pi}} = 2\times\frac{2}{\sqrt{\pi}}}= \frac{4}{\sqrt{\pi}}} \ cm$

Now Area of Circle $C_2 = \pi {r_2}^2 = \pi \times (\frac{4}{\sqrt{\pi}})^2= \pi \times \frac{16}{\pi} = 16\ cm^2$

Hence Area of Circle $C_2$  is  $16 \ cm^2$.