Question

circle:chord and arc std 8 maharastra board​

Answer 1

Answer:

AB=AP+PB.......A-P-B

AB = PB+PB.......GIVEN

AB=2PB

80=2PB....GIVEN

PB=40cm.....(1)

OB=41cm....given

In triangle OPB

OP perpendicular to AB

Therefore angle P is 90 degree

OB×OB=OP×OP+PB×PB.....by therome pythagoras

41×41=OP×OP+40×40

1681=OP×OP+1600

OP×OP=1681-1600

OP×OP=81

taking square root on both side

OP = 9cm

Step-by-step explanation:

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