circle:chord and arc std 8 maharastra board
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AB=AP+PB.......A-P-B
AB = PB+PB.......GIVEN
AB=2PB
80=2PB....GIVEN
PB=40cm.....(1)
OB=41cm....given
In triangle OPB
OP perpendicular to AB
Therefore angle P is 90 degree
OB×OB=OP×OP+PB×PB.....by therome pythagoras
41×41=OP×OP+40×40
1681=OP×OP+1600
OP×OP=1681-1600
OP×OP=81
taking square root on both side
OP = 9cm
Step-by-step explanation:
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