circle chp 3 of std 10th solve it I will give you a brilliant points
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DE=16
hence DF=8
D=20
R=10
by Pythagoras theorem
100-64=FC^2
FC=√36=6cm
hence DF=8
D=20
R=10
by Pythagoras theorem
100-64=FC^2
FC=√36=6cm
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0
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