Question

circle chp 3 of std 10th solve it I will give you a brilliant points /don't spam itt ✌✌✌✌


first thereom which has to used is 1. line segment joining the centre of the circle and midpoint a chord is perpendicular to the chord

2. by Pythagoras thereom


this two thereom used and a solve question give me a fast ans
then only I will give you a brilliant points don't wait start giving answer

Answer 1

Op^2+Qp^2=r^2
Qp=pr (theorem of line joining center to a chord)
r=root over(144+100)
=15.6

Answer 2

${OP}^{2} + { PQ}^{2} = {OQ}^{2}$
OQ=144+100=244
=15.4