circle, is bisected at the point of contact.
Or
Prove that the lengths of tangents drawn from an external point to a circle are equal.
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let a circle with centre O
PT,PQ are tangents
we know that tangents are perpendicular to radius of circle.
so angle QPT=AnglePQT. equation 1
and angle opq=angle opq(op is equal to oq). equation 2
so
subtracting eq.2from 1,we get
angle qpt equal to pqt
so,pt=qt (opposite angles are equal). proved..?..
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