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Circle touches x axis at 0 2 and passes through (2 12) the circle will also passes through

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Answered by vanshu1325
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Secondary School Math 5 points

Find the equation of circle which touches x axis at (3,0) and passes through (1,4)

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shashankavsthi

shashankavsthi Ace

Since circle is touching X axis at (3,0)

so centre must be (3,k).

And it is passing through( 1,4)

by using distance formula-

\sqrt{ {(k - 4)}^{2} + {(3 - 1)}^{2} } = \sqrt{ {(k)}^{2} + 0} \\ sq. \: both \: sides - \\ {(k - 4)}^{2} + 4 = {k}^{2} \\ \\ 16 - 8k + 4 = 0 \\ k = \frac{5}{2} \\ \\ centre \: = (3, \: \frac{5}{2} )

radius is 3

so \: now \: eq. \: will \: be - \\ {(x - 3)}^{2} + {(y - \frac{5}{2}) }^{2} = {3}^{2}

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