Question

Circle with centre o, tangents are drawn from external point pa and pb . then prove that it is an eqilateral triangle

Answer 1

In triangle POA and POB
PA=PB. (tangent drawn from external point is equal)
PO=PO. (common angle)
AO=BO. (radii of same circle)
therefore triangle POA is congruent to POB
$\frac{po}{po} = \frac{ oa}{ob } = \frac{pa}{pb}$
consider 2 and 3
hence proved