Circle(x-1)^2 + (y+3)^2 = r^2 touches the line 3x + 4y=11 , then the value of r is
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Answer:
R = 4
Step-by-step explanation:
The center of the circle is C(1,-3). Get the distance of this point to the line 3x+4y = 11. Coincidentally, this should also be the radius of the circle.
So, by distance formula of a point to line:
R = |Ax +By + C| / (√A²+B²)
R = [(3×1) + (-3×4) + (-11)] / √(3²+4²)
R = 4
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