Math, asked by srijadutta2014, 9 months ago

Circle(x-1)^2 + (y+3)^2 = r^2 touches the line 3x + 4y=11 , then the value of r is
Noone is answering any question of mine please ans someone

Answers

Answered by paulmdevera
2

Answer:

R = 4

Step-by-step explanation:

The center of the circle is C(1,-3). Get the distance of this point to the line 3x+4y = 11. Coincidentally, this should also be the radius of the circle.

So, by distance formula of a point to line:

R = |Ax +By + C| / (√A²+B²)

R = [(3×1) + (-3×4) + (-11)] / √(3²+4²)

R = 4

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