Question

circle x has a radius of and circle y has a circumference of 8. circle z has an area of 9. list them from least to greatest radius.

how do you solve this???

Answer 1

Answer:

The given circle is (x+1)2+(y+2)2=9, which has radius =3.

The given circle is (x+1)2+(y+2)2=9, which has radius =3.The points on the circle which are nearest and farthest to the point P(a, b) are Q and R, respectively.

The given circle is (x+1)2+(y+2)2=9, which has radius =3.The points on the circle which are nearest and farthest to the point P(a, b) are Q and R, respectively.Thus, the circle centred at Q having radius PQ will be the smallest circle while the circle centred at R having radius PR will be the largest required circle.

The given circle is (x+1)2+(y+2)2=9, which has radius =3.The points on the circle which are nearest and farthest to the point P(a, b) are Q and R, respectively.Thus, the circle centred at Q having radius PQ will be the smallest circle while the circle centred at R having radius PR will be the largest required circle.Hence, difference between their radii =PR−PQ=QR=6.

Answer 2

Step-by-step explanation:

However, since the late 1980s, both countries have successfully rebuilt diplomatic and economic ties. In 2008, China became India's largest trading partner and the two countries have also extended their strategic and military relations.