Circles ICSE 10. QUESTION NO. 10 B)
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Angle BOD = 2(Angle BAD)
(inscribed angle theorem)
y = 2(50°)
y = 100°
Quadrilateral ABCD is a cyclic quadrilateral.
Therefore, Angle B + Angle A = 180°
x+50° = 180°
x = 180°-50°
x = 130°
Hence,
(inscribed angle theorem)
y = 2(50°)
y = 100°
Quadrilateral ABCD is a cyclic quadrilateral.
Therefore, Angle B + Angle A = 180°
x+50° = 180°
x = 180°-50°
x = 130°
Hence,
Answered by
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Answer:
y=2*50
=100
Step-by-step explanation:
x+50=180
x=30
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