Circles S, = x2 + y2 - 4x – 6y - 3 = 0 & Sy = x2 + y2 + 2x + 2y + 1 = 0
On the basis of above information, answer the following questions :
The total number of common tangents of S, = 0 & Sy = 0 is/are
Answers
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Step-by-step explanation:
The two circles are
x
2
+y
2
–4x–6y–3=0 and x
2
+y
2
+2x+2y+1=0
Centre:C
1
=(2,3)
C
2
=(–1,–1)
radii : r
1
=4,r
2
=1
We have C
1
C
2
=5=r
1
+r
2
,
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