Math, asked by farhanakbar2614, 24 days ago

Circles S, = x2 + y2 - 4x – 6y - 3 = 0 & Sy = x2 + y2 + 2x + 2y + 1 = 0
On the basis of above information, answer the following questions :
The total number of common tangents of S, = 0 & Sy = 0 is/are

Answers

Answered by coolabhi130711
0

Step-by-step explanation:

The two circles are

x

2

+y

2

–4x–6y–3=0 and x

2

+y

2

+2x+2y+1=0

Centre:C

1

=(2,3)

C

2

=(–1,–1)

radii : r

1

=4,r

2

=1

We have C

1

C

2

=5=r

1

+r

2

,

Similar questions