Circles with centre a b c touch each other externally if ab = 3 BC = 3 and ac = 4 then find the radii of circles
Answers
Step-by-step explanation:
Given Circles with centre a b c touch each other externally if ab = 3 BC = 3 and ac = 4 then find the radii of circles
- Let the radius of the circles centred at A, B and C be p,q,r respectively. As the circles touch each other externally and ab = 3 will be p + q = 3-------------1
- Also BC = 3 will be q + r = 3 ------------ 2
- Also ac = 4 will be p + r = 4---------------3
- Adding all the three equations we get
- 2(p + q + r) = 10
- Or p + q + r = 5 ---------------4
- Subtracting equation 2 from 4 we get
- So p + q + r – q – r = 54 – 3
- Or p = 2
- Now p + q = 3
- Or 2 + q = 3
- Or q = 1
- Now p + q + r = 5
- Or 2 + 1 + r = 5
- Or r = 5 – 3
- Or r = 2
Or the radii of the circles will be 2 cm, 1 cm and 2 cm
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https://brainly.in/question/7956450
Circle with centre a,b,c touch each other externally . If ab=3, bc=3, ac=4 then, the radii of circles will be2 cm, 1 cm and 2 cm.
Stepwise explanation is given below:
- In the given circles with centre a b c touch each other externally if ab = 3, bc = 3 and ac = 4 then find the radii of circles
- The radius of the circles centred at a,b and c be p,q,r respectively. As the circles touch each other externally and
ab = 3 will be p + q = 3......(1)
bc = 3 will be q + r = 3 ......(2)
ac = 4 will be p + r = 4......(3)
- Adding all the (1),(2) and (3) we get
2(p + q + r) = 10
p + q + r = 5 ......(4)
- Subtracting equation (2) from (4) we get
So, p + q + r – q – r = 54 – 3
p = 2
- Now p + q = 3
2 + q = 3
q = 1
- Now p + q + r = 5
2 + 1 + r = 5
r = 5 – 3
r = 2
- Or the radii of the circles will be 2 cm, 1 cm and 2 cm.