circles with centres A,B,C and radius 5 cm each touch each other externally in points D,E,F 1) To find perimeter of ∆ ABC 2) What is the length of side DE of ∆DEF
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side of triangle ABC=distance between the center A and Be=10cm
the length of sides of triangle ABC is equal as the distance between the center of circles is same because of same radii
perimeter of equilateral triangle= 3×side
= 3×10
= 30
the length of sides of triangle ABC is equal as the distance between the center of circles is same because of same radii
perimeter of equilateral triangle= 3×side
= 3×10
= 30
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Answer: Helping hand
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