Question

circuit has a 2A fuse.What is maximum number of 60W (220V) bulbs that can be safely used in the circuit?​

Answer 1

★ Given Question :

• circuit has a 5A fuse.What is maximum number of 60W (220V) bulbs that can be safely used in the circuit?

★ Required Solution :

✯ Values Given to us :

• ⟹ circuit has a 2A fuse

• ⟹ 60W (220V) bulbs

✯ Formula Used Here :

• ⟹ P = V × I

• ⟹ n = Power of circuit / power of bulb

★ Finding Power in Circuit :

• ⟹ I = 2A

• ⟹ V = 220V

✯ Putting value in formula :

• ⟹ P = 220 × 2

• ⟹ P = 440 watt

✯ Number of Bulbs ( 60 W ) :

• ⟹ n = Power of circuit / power of bulb

• ⟹ n = 440/60

• ⟹ n = 7.333 = 7 ( Approx)

✫ 7 Bulbs of 60 W is Used in Circuit.

_____________________________

Answer 2

$\huge \sf{ \underline{ \pink{ \underline{ \blue{ \underline{ \pink{ \underline{ \blue{answer❤}}}}}}}}}$

Given that:-

$\bold \pink{ = > circuit \: has \: a \: 2a \: fuse}$

$\bold \blue{ = >60w \: (220v) \: bulbs}$

Formula :-

$\bold \orange{ = > p = V\times I}$

$\bold \green{ = > n = power \: of \: circuit/ \: power \: of \: bulb}$

Power in Circuit :-

$\fbox \red{ = > I = 2a}$

$\fbox \pink{ = > v = 220V}$

Value in formula !❤

$\red{ = > p = 220 \times 2}$

$\pink{ = > p = 440 \: watt}$

Number of bulbs:-

• 60 W

$\underline \green{ = > n = power \: of \: circuit \: / \: power \: of \: bulb}$

$\underline \orange{n = 440/60}$

$\underline \purple{ = > n = 7.333 \: = 7}$

$\huge \fbox \red{7 \: bulbs \: are \: required}$