Question

circular
11. Find the cost of polishing a
tabletop of radius 2.8 m, if the rate of
polishing is 720/m2.​

Answer 1

Answer:

Area of tabletop is ,

$\pi {r}^{2} = \frac{22}{7} \times2.8m \times 2.8m = 24.64 {m}^{2}$

therefore,

cost of polishing the tabletop,

$rs. \: 24.64 \times 720 = rs.17740.8$

Thanks.