Question

Circular Motion
question from cengage.
A particle P of mass m is attached
to a vertical axis by two strings
AP and BP of length I each.
The separation AB = 1. P rotates
around the axis with an angular
velocity 0. The tensions in the
two strings are T, and T. Choose
the correct option(s).
the one who give correct answer will be marked as brainlist​

ONLY FOR IITIANS

Answer 1

Answer:

(T1 + T2) = mω2l    

Explanation:

The ΔABP will be an equilateral trianlge. Let T1 and T2 be tensions in PA and PB respectively.

Then, considering the vertical forces;

T1 cos 60 = T2 cos 60 + mg

or,   T1/2− T2/2 = mg

or,    T1 −  T2=2mg

Now taking the horizontal components;

T1 sin 60 +  T2 sin 60 = mrω2

r = l√3/2

or,

(T1 + T2) √3 / 2 = mω2l  √3 / 2

(T1 + T2) = mω2l