Question

circular piece of thin wire is converted into a rhombus of side 11cm . find the diameter of the circular piece​

Answer 1

Step-by-step explanation:

Since, circular piece of thin wire is converted into a rhombus.

Therefore,

Circumference of circle = Perimeter of rhombus

$\therefore \: 2\pi \: r = 11\times 4 \\ \therefore \: 2 \times \frac{22}{7} \times \: r = 44 \\ \therefore \: r = \frac{44 \times 7}{2 \times 22} \\ \therefore \: r = \frac{44 \times 7}{44} \\ \therefore \: r = 7 \: cm \\ \therefore \:d = 2 \times r \\ \therefore \:d =2 \times 7 \\ \therefore \:d =14 \: cm$

Thus, the diameter of the circular piece is 14 cm.

Answer 2

Step-by-step explanation:

2πr=11×4

2×22/7×r=44

r=44×7/2×22

r=7

d=2×r

d=2×7

d=14