Question

circular road runs around a circle garden if the circumference of outer circle and the inner circle are 110 metre and 88 metre find the width of the road​

Answer 1

Answer:

3.5 m

Step-by-step explanation:

Circumference = 2\pi r2πr

Since we are given that the circumference of the outer circle is 110 m

So, 110 = 2\pi r110=2πr

Where r is the radius of outer circle .

55 = \frac{22}{7} r55=

7

22

r

55 \times \frac{7}{22}= r55×

22

7

=r

5 \times \frac{7}{2}= r5×

2

7

=r

\frac{35}{2}= r

2

35

=r

17.5= r17.5=r

Thus the outer radius is 17.5 m

Now we are also given that circumference of the the inner circle is 88 m .

So, 88 = 2\pi r88=2πr

44 = \frac{22}{7} r44=

7

22

r

44 \times \frac{7}{22}= r44×

22

7

=r

4 \times \frac{7}{2}= r4×

2

7

=r

14= r14=r

Thus the inner radius is 14 m.

Width of road = Outer radius - inner radius

= 17.5 - 14

= 3.5 m

Thus the width of the road is 3.5 m