Question

circum center of a triangle with vertices (4,6),(2,1),(-3,5)​

Answer 1

Circum centre formula = [(x1+x2+x3)/3] , [(y1+y2+y3)/3]

                                       = [(4+2-3)/3] , [(6+1+5)/3]

                                       = [(3/3)] , [(12/3)]

                                       = (1) , (4)

Therefore the vertices of the circum centre are ( 1,4 )

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