Question

Circumference of base of a cylinder open at the top is 132 cm The sum of
radius and height is 41 cm find the cost of polishing the outer surface area of cylinder at the rate Rs 10 square cm

please tell correct answer I will mark brainiest ​

Answer 1

Answer:

Step-by-step explanation:

given:

2πr=132cm

r+h=41cm

Sol:

2×22/7×r=132cm

22/7×r=132/2cm

22/7×r=66cm

22×r=66×7cm

r=462/22cm

r=21cm

r+h=41cm

21+h=41cm

h=41-21cm

h=20cm

T.S.A= 2πr(r+h)cm^2

= 2×22/7×21(41)cm^2

=132×41cm^2

=5412cm^2

change cm in m=5412/1000

cost of polishing the outer surface area of cylinder at the rate of rupee 10 per square metre =

TSA×rate of polishing the cylinder

=5412/1000×10ruper

=5412/100rupee

=276/50rupee

=138/25rupee

=5.52 rupee

Answer 2

Answer:

please answer

Step-by-step explanation:

I will mark brainliest with correct answer