Circumference of fore wheel of a car is 2 m and circumference of rear wheel is 3 n m. If fore wheel makes 10 revolu tions more than rear wheel. What will be distance covered
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1
fore whel makes to rordution more than are wheel distance converted =120 m
Let rd1 be diameter of five wheel and rd2 be diameter of area wheel then
πd1
120
=
πd2
120
+10..(1)
later diameter of five wheel is increased by 1/4
π(
4
5
d1)
120
=
πd2
120
+6
⇒
πd1
96
=
πd2
120
+6...(2)
substitude (1) in (2)
⇒
πd1
96
=
πd1
120
−10+6
⇒
πd1
120
−
πd1
96
=4
⇒ πd1=6 circumference of for wheel
Substuting πd1 in (3)
we get πd2=12 rase wheel.
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