Question

Circumference of the base of a cylinder open at the top is 132 cm. The sum of radius and
height of the cylinder is 41 cm. Find the cost of polishing the outer surface of cylinder at the
rate of Rs. 10 per sq.cm​

Answer 1

Answer:

Here given Circumference of the base of a cylinder open at the top is 132cm.

2πr=132

r=132/2π=21.

Also given that

The sum of the radius and height of the cylinder is 41cm.

r+h=41

h=41-r=41-21=20.

Given that top of the cylinder is open.So that total area is

=πr(r+2h)

=21π(21+40)

=4026cm^2=0.4026m^2.

The cost of polishing the outer surface of cylinder at the rate of ₹400 per m2 is

0.4026×400=161.04 ₹

Step-by-step explanation:

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