Question

Circumference of the base of cylinder open at top is 132 cm the sum of radius and height of cylinder is 41 cm find the cost of polishing the outer surface of cylinder at the rate of rupee 10 per sq metre

Answer 1

given:
2πr=132cm
r+h=41cm
Sol:
2×22/7×r=132cm
22/7×r=132/2cm
22/7×r=66cm
22×r=66×7cm
r=462/22cm
r=21cm
r+h=41cm
21+h=41cm
h=41-21cm
h=20cm
T.S.A= 2πr(r+h)cm^2
= 2×22/7×21(41)cm^2
=132×41cm^2
=5412cm^2
change cm in m=5412/1000
cost of polishing the outer surface area of cylinder at the rate of rupee 10 per square metre =
TSA×rate of polishing the cylinder
=5412/1000×10ruper
=5412/100rupee
=276/50rupee
=138/25rupee
=5.52 rupee

Answer 2

Answer:

Refer to attachment

Hope it helps..