Question

circumference of the inner and Outer circle of a track are 220 m and 264m. find the area of the track. seating arrangement for the spectators occupy 40m width all around. how much area has been covered for the spectators

Answer 1

Answer:

Step-by-step explanation:

We need to get both the inner radius and the outer radius.

The circumference of a circle = pie × 2r

The outer circle :

264 = 22/7 × 2r

264 = 44/7r

r = 264 × 7/44 = 42m

The inner track is :

220 = 22/7 × 2r

220 = 44/7r

r = 220 × 7/44

r = 35m

The area of the track = Outer area - inner area.

Inner area = 22/7 × 35 × 35 = 3850

Outer area = 22/7 × 42 × 42 = 5544

Area of the track = 5544 - 3850 = 1694

= 1694 square meters.

If the spectators occupy upto to 40m.

The new radius from outer circle is :

42m + 40m = 82m

The area of the outer circle formed by the spectators is :

22/7 × 82 × 82 = 21132.57

The area occupied by spectators is thus :

21132.57 - 5544 = 15588.57

= 15588.57 square meters.