circumradius of circumcircle formed by (-2,-3) (-1,0) and (7,-6)
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A, B, C be the vertices of the triangle and ,y) be its circumcentre. Then DA = PB = PC %3D PA? = PB? = PC² 2, PA? = PB? æ + 2)² + (y + 3)² = (x + 1)² + y? 2 + 4x + 4 + y? + 6y + 9 = x2 + 2x +1+y? x + 6y + 12 = 0 = x + 3y+6 = 0 .(1) in PB? = PC? (x + 1)² + (y – 0)² = (x – 7)² + (y + 6)² a? + 2x +1+ y² = x² – 14x + 49 + y + 12y + 36 .6x – 12y – 84 = 0 4.x – 3y = 21 ..(2) ing (1) and (2),we get x = 3 and y = -3 Circumcentre = (3, -3) CLOSE
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