Cities A, B and c are equidistant from
each other. A motorist travel from AtoB
Km/h: from B to c at 40km/h and from
C toA at 50 km/h determine his Average
Speed for the entire trip
Answers
Answered by
0
Answer:
30km/h the average speed
Answered by
4
Answer:38.3km/h
Explanation:*A*, *B* and *C* are equidistant.
Let distance *AB=BC=CA=x cm*.
Speed= Distance/time.
Time=Distance/Speed.
Total distance = *x + x + x = 3x* cm
Total Time;
*AB*= x/30, *BC*=x/40, and *CA*=x/50.
*(x/30) + (x/40) + (x/50) = (47x/600)*
*Average Speed = Total Distance/Total Time*.
*Av S =(3x ÷ 47x/600)*
= *3x* X *600*
------------------
*47x*
= *1800*
---------
*47*
= *38.3km/h*
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