CitLosa) (1-COSA) 3/4
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Answer:
Given (1+cosA)(1−cosA)=
4
3
⟹1−cos
2
A=
4
3
⟹cos
2
A=1−
4
3
⟹cos
2
A=
4
4−3
⟹cos
2
A=
4
1
⟹sec
2
A=4
⟹secA=±2
Hope it helps you!!!!!
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