Question

City A and City B had two different temperatures on a particular day. On that day, four times the temperature of City A was 8° C more than 3 times the temperature of City B. The temperature of City A minus twice the temperature of City B was −3° C. What was the temperature of City A and City B on that day? City A was 5° C, and City B was 4° C. City A was 3° C, and City B was −1° C. City A was 8° C, and City B was −3° C. City A was 5° C, and City B was −5° C.

Answer 1

let temp. of city A be x
and temp of city B be y

given that,
4x = 3y + 8
x - 2y = -3


==>4x - 3y = 8 ---------(1)
==>x - 2y = -3 ---------(2)

mul (2) by (4)
4x - 8y = -12 ----------(3)
do (1) - (3)
5y = 20 => y = 4
sub in (2)
x - 2(4)= -3
x = 8-3 => x=5


so Temperature of City A was 5° C, and Temperature of City B was 4° C

Answer 2

Answer:

i know this one is A because i got it right

Explanation: