City-A has a population of P, while City-B has a population of 2 P. The population of City-A grows at the rate of 20 per annum while the population of City-B declines at the rate of 20 per annum. After 2 years, what will the population of City-B be?
Answers
Answered by
3
Answer:32p/25
Step-by-step explanation:
Population of City B after 1 year = 2p *80/100
= 2p*4/5 =8p/5
Population City B in the second year = 8p/5 *80/100
= 8p/5 * 4/5
= 32p/25 = ans.
Answered by
2
City-A = P(1+20/100)^2
= P(120/100)^2
= P((120*120)/(100*100))
= P(12*12/100)
= P(144/100)
= P*1.44 (or 1.44P)
City-B = 2P(1-20/100)^2
= 2P(80/100)^2
= 2P((80*80)/(100*100))
= 2P(8*8/100)
= 2P(64/100)
= 2P*0.64 (or P*2*0.64)
= P*1.28 (or 1.28P)
Thank You, Hope it helped! (Please mark me as brainliest if it did)
The Above answer is also correct but this is a detailed way
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