City B is 5 km east of city A. City C is 12km south of city B. What is the shortest distance between A and C?
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Answer:
13 km
Explanation:
City b is 5 km east and city c is 12 km south
This forms a right angled triangle
So 5²+12²=x²
25+144=x²
169= x²
X = 13km
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