City X is 40 Km North from city Y. City Z is 30 km west from city X and
City P is 45 km East from city Y. There is no other straight road to access
from city Y to city Z. How long the distance between City Y and Z?
(A) 50 km
(B) 70 km
(C) 75 km
(D) 115 km
Answers
Answered by
1
Answer:
70 is the answer because in between city x and city y is 40 kn south and city z is 30 km west. So, 40+30=70
Answered by
1
Answer: (A) 50 Km
Step-by-step explanation:
Now after drawing the map-work of the given question, we get that points of the cities X, Y and Z form a right-angled triangle where ZX = 30 Km and
XY = 40 Km.
Through the Pythagoras Theorem, we know that in a right-angled triangle, the sum of the squares of the sides adjoining the right angle of the triangle is always equal to the square of the hypotenuse and ZY is the hypotenuse in this case.
→ ZX² + XY² = (30)² + (40)² = 2500 Km
→ ZY² = 2500 Km
⇒ ZY = 50 Km
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