Math, asked by bjusadk5, 11 days ago

City X is 40 Km North from city Y. City Z is 30 km west from city X and

City P is 45 km East from city Y. There is no other straight road to access

from city Y to city Z. How long the distance between City Y and Z?

(A) 50 km

(B) 70 km

(C) 75 km

(D) 115 km​

Answers

Answered by kumarinutansi1991
1

Answer:

70 is the answer because in between city x and city y is 40 kn south and city z is 30 km west. So, 40+30=70

Answered by Acer27
1

Answer: (A) 50 Km

Step-by-step explanation:

Now after drawing the map-work of the given question, we get that points of the cities X, Y and Z form a right-angled triangle where ZX = 30 Km and

XY = 40 Km.

Through the Pythagoras Theorem, we know that in a right-angled triangle, the sum of the squares of the sides adjoining the right angle of the triangle is always equal to the square of the hypotenuse and ZY is the hypotenuse in this case.

→ ZX² + XY² = (30)² + (40)² = 2500 Km

→ ZY² = 2500 Km

⇒ ZY = 50 Km

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