cl2(chlorine) has 2 isotopes of atomic mass unit 34.97u and 36.97u the relative abundance of these two isotopes are 0.735 and 0.245 respectively. Find out the average atomic mass of chlorine.
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Average atomic mass = (34.97 x 0.735 + 36.97 x 0.245)/ (0.735+0.245)
= (25.70295 + 9.05765)/0.98
= 35.47u
= (25.70295 + 9.05765)/0.98
= 35.47u
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