Cl2 + NaOH upon heating what will b the product ?
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NaOH + Cl2 -> 5NaCl + NaClO3 + 3H2O
The product is sodium chlorate(V) - NaClO3.
As before, check the oxidation states of everything in the equation. Once again, you will find that the only thing to have changed is the chlorine. It goes from 0 in the chlorine molecules on the left-hand side to -1 (in the NaCl) and +5 (in the NaClO3).This is also a disproportionation reaction.
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