Question

Cl2+OH- ---->CL- +CLO3- +H2O

Answer 1

$Cl_2 + OH^- \rightarrow Cl^-+ ClO_3^-+H_2O$

Oxidation half:

$Cl_2 \rightarrow2 ClO_3^-+10e^-$

$Cl_2 +12OH^-\rightarrow2 ClO_3^-+10e^-+6H_2O....(i)$

Reduction half:

$Cl_2 +2e^-\rightarrow2Cl^-$

×5 ⇒ $5Cl_2 +10e^-\rightarrow10Cl^-....(ii)$

(i) + (ii)

$6Cl_2+12OH^-\rightarrow2ClO_3^-+10Cl^-+6H_2O$

$3Cl_2+6OH^-\rightarrow ClO_3^-+5Cl^-+3H_2O$

That is the final balanced equation

HOPE THIS HELPS!!