cl2o7 reaction with h2o2 in basic medium can anyone please solve this with detailed steps
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Explanation:
The oxidation number of Cl decreases from + 7 in Cl2O7 to + 3 in and the oxidation number of ClO2- increases from – 1 in H2O2 to zero in O2. Hence, in this reaction, Cl2O7 is the oxidizing agent and H2O2 is the reducing agent as could be clearly seen in the figure below
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