Question

Claas 10th
Science 1
Two rungsten bulbs of wattage 100 W nad 60 W power work on 220 V potential difference. If they are connected in parallel how much current will flow in main conductor ?
plz answer me fast it's really urgent ​

Answer 1

Answer:

according to ohm law

V=IR or I=V/R

now two bulbs are in parallel, and voltage remain same in parallel circuit oky.

that's why from P=V²/R we can find the resistances of each bulbs

Let, First bulb is L1 and second one L2

for L1

R1=V²/P1= 220*220/100=22*22=484 ohm

for L3

R2=V²/P2=220*220/60=220*11/3=2420/3 ohm

Now this two are connected in parallel so equivalent resistance

Rē=(484*2420/3)/(484+2420/3)=390427/1291

=302.42 ohm

so maine circuit current

I=V/Rē= 220/302.42=0.727≈0.73 A

Answer 2

$\textbf{Given:}$

$⇒P_{1} = 100 \: W$

$⇒P_{2} = 60 \: W$

$⇒V = 220 \: V$

$\textbf{To Find: I = ?}$

$\textbf{Formula: P = VI}$

$\sf \colorbox{pink} {Solution:}$

$\text{Total Power:}$

$⇒(P) = P_{1} + P_{2} = 100 + 60 = 160 \: W$

$⇒P = VI$

$⇒I = \frac{P }{V} = \frac{160}{220} = \frac{8}{11}$

$\fbox{I = 0.72 A}$

$\\ \\ \\ \\ \\ \sf \colorbox{gold} {\red(ANSWER ᵇʸ ⁿᵃʷᵃᵇ⁰⁰⁰⁸}$