Question

claculate depression in freezing point of a 0.2 molal solution if kf for water is 1.86 k kg mol​

Answer 1

Given,

• Molality (m) = 0.1 molal

• Freezing point depression constant $\displaystyle\sf{(K_f)}$ = 1.86 C/m

The depression in freezing point ,

$\boxed{\displaystyle\sf{\Delta T_f=m\times K_f}}$

Applying the values to the equation,

$\implies\displaystyle\sf{\Delta T_f=0.2\times 1.86}$

$\implies\displaystyle\sf{\Delta T_f=0.372\:K}$

$\boxed{\bold{\displaystyle\sf{Depression\:in\:Freezing\:Point\:(\Delta T_f)=0.372\:K}}}$