Chemistry, asked by gayatrirajurkar869, 5 months ago

Claculate standed enthalpy of of reaction
2 C2 H6 + 702 -4CO2 + 6H2O
Given that
Hº(co 2) = -393.5 klmol , Hº (H20)
= -285.8 klmol-1
4. Hº (C2H6) = -84.9 klmol-1​

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Answered by karamjeetkaur1977
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