Science, asked by Rohit111223, 1 year ago

Claculate the energy transferred by a5A current flowing through a resistor of 2ohms for 30 minutes.

Answers

Answered by Anonymous

2

R=2ohm.
I =5A
t=30min 30×60sec.
H =I²Rt
5×5×2×30×60
25×60×60.
Power =W/t
25×60×60/30×60
50J/s
energy =P×t

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