Question

claculate the force of attraction between a proton and an electron kept seperated by a distance of
$3 \times 10 ^ - 8$
​

Answer 1

Answer:

F=Kq1q2/r^2

=9*10^9*(1.6*-1.6)*10^-38/9*10^-16

= 2.56*10^-13 N

Explanation: